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Neutral losses and fragment groups

What a parent ion can lose, what remains, and by how much mass

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Neutral losses and fragment groups

Enter the precursor formula to list feasible neutral losses (are there enough atoms, what formula is left, how much mass), plus searchable fragment-group and adduct tables.

Enter the precursor formula to list feasible neutral losses (are there enough atoms, what formula is left, how much mass), plus searchable fragment-group and adduct tables.

Every calculation runs locally in your browser. Nothing you type is ever uploaded.

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Given a parent formula, this section checks the common neutral losses one by one (H2O, NH3, CO, CO2, CH3, C2H4, SO2 and more) to see whether the current atoms can actually support each loss, what formula would remain and what the mass difference is. Losses that are chemically impossible are marked as such instead of being silently listed.

The same section includes a searchable table of fragment groups and adduct ions: look up common fragments (C3H7+, C6H5+ and similar) or adducts by name, formula or approximate mass, and match what you measured to what is known.

How to use it

  1. Enter the parent formula (neutral or ion notation).
  2. Read the neutral loss table: each feasible row shows the remaining formula and the mass difference.
  3. Match the mass differences against the fragment peaks in your spectrum.
  4. Use the fragment group and adduct tables below to identify what remains.

Frequently asked questions

Why are some losses crossed out?
A neutral loss must be possible from the actual atoms: without enough hydrogen you cannot lose H2O, without nitrogen you cannot lose NH3. The tool checks each candidate against the element counts of the parent, so impossible fragments are ruled out for you.
Why do the mass differences carry so many decimals?
The decimals separate losses that share a nominal mass but differ in composition: losing CO (27.9949) and losing C2H4 (28.0313) both look like 28 at low resolution, yet the exact values differ.
Is anything I type uploaded?
No. There is no back end: the algorithms, the NIST isotope data and every dictionary ship with the page, and all calculations run in your browser.
How accurate is the data?
Isotope masses and abundances come from a NIST snapshot (94 elements, 298 isotopes). Isotope distributions are exact polynomial convolutions and agree with mainstream simulators to several decimal places.
Is it free? Do I need an account?
It is completely free, with no usage limit and no sign-up or login.
Can I send a calculation to someone else?
Yes. Click Copy link and the input state is encoded into the URL hash, so opening that link restores exactly what you had.

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